TSTP Solution File: SEV388^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEV388^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 19:24:52 EDT 2023

% Result   : Theorem 3.45s 3.64s
% Output   : Proof 3.45s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEV388^5 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n021.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Thu Aug 24 02:53:54 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.45/3.64  SZS status Theorem for theBenchmark.p
% 3.45/3.64  SZS output start Proof for theBenchmark.p
% 3.45/3.64  Clause #0 (by assumption #[]): Eq (Not (Eq cR cS → ∀ (Xx : Iota), cR Xx → cS Xx)) True
% 3.45/3.64  Clause #1 (by clausification #[0]): Eq (Eq cR cS → ∀ (Xx : Iota), cR Xx → cS Xx) False
% 3.45/3.64  Clause #2 (by clausification #[1]): Eq (Eq cR cS) True
% 3.45/3.64  Clause #3 (by clausification #[1]): Eq (∀ (Xx : Iota), cR Xx → cS Xx) False
% 3.45/3.64  Clause #4 (by clausification #[2]): Eq cR cS
% 3.45/3.64  Clause #5 (by argument congruence #[4]): ∀ (a : Iota), Eq (cR a) (cS a)
% 3.45/3.64  Clause #8 (by clausification #[3]): ∀ (a : Iota), Eq (Not (cR (skS.0 0 a) → cS (skS.0 0 a))) True
% 3.45/3.64  Clause #9 (by clausification #[8]): ∀ (a : Iota), Eq (cR (skS.0 0 a) → cS (skS.0 0 a)) False
% 3.45/3.64  Clause #10 (by clausification #[9]): ∀ (a : Iota), Eq (cR (skS.0 0 a)) True
% 3.45/3.64  Clause #11 (by clausification #[9]): ∀ (a : Iota), Eq (cS (skS.0 0 a)) False
% 3.45/3.64  Clause #14 (by superposition #[11, 5]): ∀ (a : Iota), Eq (cR (skS.0 0 a)) False
% 3.45/3.64  Clause #15 (by superposition #[14, 10]): Eq False True
% 3.45/3.64  Clause #16 (by clausification #[15]): False
% 3.45/3.64  SZS output end Proof for theBenchmark.p
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