TSTP Solution File: SEV388^5 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SEV388^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:52 EDT 2023
% Result : Theorem 3.45s 3.64s
% Output : Proof 3.45s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEV388^5 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n021.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Thu Aug 24 02:53:54 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.45/3.64 SZS status Theorem for theBenchmark.p
% 3.45/3.64 SZS output start Proof for theBenchmark.p
% 3.45/3.64 Clause #0 (by assumption #[]): Eq (Not (Eq cR cS → ∀ (Xx : Iota), cR Xx → cS Xx)) True
% 3.45/3.64 Clause #1 (by clausification #[0]): Eq (Eq cR cS → ∀ (Xx : Iota), cR Xx → cS Xx) False
% 3.45/3.64 Clause #2 (by clausification #[1]): Eq (Eq cR cS) True
% 3.45/3.64 Clause #3 (by clausification #[1]): Eq (∀ (Xx : Iota), cR Xx → cS Xx) False
% 3.45/3.64 Clause #4 (by clausification #[2]): Eq cR cS
% 3.45/3.64 Clause #5 (by argument congruence #[4]): ∀ (a : Iota), Eq (cR a) (cS a)
% 3.45/3.64 Clause #8 (by clausification #[3]): ∀ (a : Iota), Eq (Not (cR (skS.0 0 a) → cS (skS.0 0 a))) True
% 3.45/3.64 Clause #9 (by clausification #[8]): ∀ (a : Iota), Eq (cR (skS.0 0 a) → cS (skS.0 0 a)) False
% 3.45/3.64 Clause #10 (by clausification #[9]): ∀ (a : Iota), Eq (cR (skS.0 0 a)) True
% 3.45/3.64 Clause #11 (by clausification #[9]): ∀ (a : Iota), Eq (cS (skS.0 0 a)) False
% 3.45/3.64 Clause #14 (by superposition #[11, 5]): ∀ (a : Iota), Eq (cR (skS.0 0 a)) False
% 3.45/3.64 Clause #15 (by superposition #[14, 10]): Eq False True
% 3.45/3.64 Clause #16 (by clausification #[15]): False
% 3.45/3.64 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------